Answer:
The correct option is b.
Step-by-step explanation:
We have to find the product of [tex]\frac{2a-7}{a}[/tex] and [tex]\frac{3a^2}{2a^2-11a+14}[/tex].
Multiply both terms.
[tex]\frac{2a-7}{a}\times \frac{3a^2}{2a^2-11a+14}[/tex]
Cancel out the common factor a from numerator and denominator.
[tex]\frac{2a-7}{1}\times \frac{3a}{2a^2-7a-4a+14}[/tex]
[tex]\frac{2a-7}{1}\times \frac{3a}{a(2a-7)-2(2a-7)}[/tex]
[tex]\frac{2a-7}{1}\times \frac{3a}{(2a-7)(a-2)}[/tex]
Cancel out the common factor (2a-7) from numerator and denominator.
[tex]\frac{1}{1}\times \frac{3a}{a-2}[/tex]
[tex]\frac{3a}{a-2}[/tex]
Therefore, the correct option is b.
