Answer:
The answer to your question is: [tex]\frac{1}{9} + 6^{9}[/tex]
Step-by-step explanation:
Data
a = 27
b = 64
[tex]a^{-2/3} + b^{3/2}[/tex]
[tex]\frac{1}{a^{2/3} } + b^{3/2}[/tex]
[tex]\frac{1}{27^{2/3} } + 64^{3/2}[/tex]
[tex]\frac{1}{(3^{3})^2/3 } + (2^{6})^{3/2}[/tex]
[tex]\frac{1} {3^{6/3} } + 6^{18/2}[/tex]
[tex]\frac{1}{9} + 6^{9}[/tex]
