Answer:
Pressure is increased by a factor of 2
Explanation:
[tex]P_{1}[/tex]=832 torr and [tex]P_{2}[/tex] is unknown
where [tex]P_{1}[/tex] is initial pressure and [tex]P_{2}[/tex] is the final pressure
[tex]V1 = V[/tex], [tex]V2 = V/2[/tex] where [tex]V_{1}[/tex] and [tex]V_{2}[/tex] are the initial and final volumes respectively
From gas laws
[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
[tex]832* V = P_{2}* \frac {V}{2}[/tex]
Pressure [tex]P_{2} = 1664 torr[/tex]
The above pressure of 1664 torr is double the pressure of 832 torr. Therefore, we conclude that the pressure is increased by a factor of 2
