Answer:
See below in bold.
Explanation:
Al2S3 + 6H2O ----> 3H2S + 2AL(OH)3 is the balanced equation.
Using molar masses :
150.14 g AL2S3 gives 2 * 78.006 g Al(OH)3
So 1 g .......................... 156,012 / 150.14 ................
16.2 g ...............................156.012 * 16.2 / 150.14 g
= 16.83 g Al(OH)3.