Answer:
s₁ = 2 m/s
Step-by-step explanation:
given,
distance between Melissa and friend = 3 mile
walking speed = s₁
bike speed = s₂
total time of the trip = 2 hour
given,
s₂ = s₁ + 4
[tex]time =\dfrac{distance}{speed}[/tex]
[tex]t =\dfrac{3}{s_1} +\dfrac{3}{s_2}[/tex]
[tex]2 =\dfrac{3}{s_1} +\dfrac{3}{s_1+4}[/tex]
2(s₁ +4)s₁ = 3 (s₁ + s₁ + 4)
2 s₁² + 8 s₁ = 6 s₁ + 12
s₁² + s₁ - 6 = 0
s₁² + 3 s₁ - 2 s₁ - 6 = 0
(s₁ + 3) (s₁ -2) = 0
s₁ = -3 , 2
s₁ = 2 m/s
walking speed of the Melissa is s₁ = 2 m/s
The walking speed was 2 miles per hour.
Since Melissa walks 3 miles to the house of a friend and returns home on a bike, and she averages 4 miles per hour faster when cycling than when walking, and the total time for both trips is two hours, to find her walking speed she must perform the following calculation:
Therefore, the walking speed was 2 miles per hour.
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