Answer:
b) 1.3 units
b) 22.61° East of North
Step-by-step explanation:
[tex]|\vec{AB}|=\sqrt{0.5^2+1.2^2}\\\Rightarrow |\vec{AB}|=\sqrt{0.25+1.44}\\\Rightarrow |\vec{AB}|=\sqrt{1.69}\\\Rightarrow |\vec{AB}|=1.3[/tex]
[tex]|\vec{AB}|=1.3\ units[/tex]
Magnitude of vector AB is 1.3 units
[tex]tan\theta=\frac{0.5}{1.2}\\\Rightarrow \theta=tan^{-1}\frac{0.5}{1.2}\\\Rightarrow \theta=22.61^{\circ}[/tex]
The direction of vector AB is 22.61° East of North
