Answer:
a 6+ 8i
b -5 + 5i
c 34i
d 8 + i
Step-by-step explanation:
a)(2 +5i)+(4 +3i)
Add them together 6 + 8i
b)(−1+2i) − (4 − 3i)
Add them together -5 + 5i
c)(5+3i)(3 +5i)
Multiply it out 15 + 25i + 9i + 15[tex]i^{2}[/tex]
Add them together ([tex]i^{2}[/tex] = the number times -1) 34i
d)(1 +i)(2 − 3i) +3i(1− i) − i
Multiply it out (2 - 3i + 2i - 3[tex]i^{2}[/tex]) + (3i - 3[tex]i^{2}[/tex]) - i
Add what is in the parenthesis together ([tex]i^{2}[/tex] = the number times -1) (5 - i) + (3 + 3i) - i
Add them together 8 + i
