Answer:
Step-by-step explanation:
Given
quadratic Equation in standard Form
a)Exactly two roots
it is Possible when Discriminant is greater than zero
D>0
for ex:
or [tex]x^2-9x+4=0[/tex]
(b)Exactly one distinct real solution
it is not Possible that one solution is real and other is complex therefore both roots are equal and real
it is Possible when Discriminant is zero
D=0
for ex [tex]\left ( x-2\right )^=0[/tex]
or [tex]x^2-4x+4=0[/tex]
(c)Exactly two complex solution
it is Possible when Discriminant is zero
D<0
[tex]\sqrt{b^2-4ac}<0[/tex]
for ex:
[tex]x^2-2x+10=0[/tex]
here D<0 therefore two complex roots exists
