Respuesta :
Answer:
The Initial vertical velocity is zero
Explanation:
Given that,
A book is pushed with an initial horizontal velocity, Vx = 5 m/s
According to projectile motion, the horizontal component of velocity i.e., in X-axis remains the same though out its path.
The vertical velocity varies i.e., the velocity towards the Y- axis.
The velocity of the falling book in its trajectory is the resultant velocity. Due to the action of gravity, it keeps on increasing with time.
The resultant velocity is given by relation
[tex]V_{R} = \sqrt{{V_{x}^{2}} +[ {gt}]^{2} }[/tex]
where
gt = Vy - vertical velocity
g - acceleration due to gravity
t - time
Since, the initial horizontal velocity at that instant is equal to the resultant velocity.
Vx = 5 m/s
[tex]V_{R}[/tex] = 5 m/s
So, on substituting in the above equation
Vy = 0 m/s
Therefore, the initial vertical velocity is equal to zero
Initial vertical velocity of the book is 0 and for better understanding refer the below solution.
Given :
Horizontal Velocity, [tex]\rm V_x[/tex] = 5 m/sec
Solution :
The velocity of the falling book in its trajectory is the resultant velocity. Due to the action of gravity, it keeps on increasing with time.
So,
[tex]\rm V_R = \sqrt{V_x^2 + V_y^2}[/tex] ----- (1)
Since the resultant velocity is equal to the horizontal velocity that is,
[tex]\rm V_R = 5\; m/sec[/tex]
Now put the values of [tex]\rm V_x \; and \; V_R[/tex] in equation (1) we get,
[tex]\rm 5 = \sqrt{5^2 + V_y^2}[/tex]
[tex]\rm V_y = \sqrt{5^2-5^2}[/tex]
[tex]\rm V_y = 0[/tex]
Therefore, initial vertical velocity of the book is 0.
For more information, refer the link given below
https://brainly.com/question/13639113?referrer=searchResults
