Answer:
Explanation:
The capacitance connected in parallel will have the same potentials across its ends. If the battery has a charge Q, it is divided among the capacitors.
That is,
Q = q₁ + q₂ + q₃
But, the potential is shared equally as V. So, the individual capacitance of the equation has the form q₁ = C₁V , q₂ = C₂V, etc.
So, in this case, when the effective capacitance is formulated, it would be
C = C₁ + C₂ + C₃ farad
Therefore, the true statements are
The equivalent capacitance of the combination is greater than the capacitance of either of the capacitors.
The potential across each of the capacitors is the same.
The charge supplied by the battery divided among the capacitors.