Answer:
Yes ,Tyiesha is correct.
Step-by-step explanation:
Lets take u vector
u = ai + b j +ck
So the magnitude of vector u given as
[tex]R=\sqrt{a^2+b^2+c^2}[/tex]
If the magnitude of above vector is zero then the values a= 0 , b= 0 and c=0 should be zero.
a= 0 , b = 0 ,c = 0
So now by putting the values
u = ai + b j +ck
u = 0 i + 0 j +0 k
u = 0 ,u is a zero vector.
It means that u should be zero vector.So Tyiesha is correct.
