Answer: The right answer is b)
Explanation:
By definition, acceleration is the change in velocity (in module or direction) over a given time interval, as follows:
a = (v-v₀) / (t-t₀)
If we take t₀ = 0 (this is completely arbitrary), we can rewrite the equation above, as follows:
v = v₀ + at
We can recognize this function as a linear one, where a represents the slope of the line.
If a is constant, this means that the relationship between the change in velocity and the change in time remains constant, in other words, in equal times, its velocity changes in an equal amount.
Let's suppose that a = 10 m/s/s. (Usually written as 10 m/s²).
This is telling us that each second, the velocity increases 10 m/s.
The only statement that describes a constant nonzero acceleration is In equal times its velocity changes by equal amounts.
Acceleration is defined as the rate of change of velocity with time.
[tex]a = \frac{\Delta v}{\Delta t} = \frac{v- u}{t_2 -t_1}[/tex]
A constant nonzero acceleration implies that the rate of change of velocity with time is constant. That is the velocity is changing at a constant rate.
For example, say we have the following table for velocity and time:
velocity (m/s) ---------- time (s)------------ acceleration (m/s²)
2 --- 4----------------------2 --- 1------------------------ 2
5-----7----------------------2-----1------------------------- 2
6 -----8----------------------- 2----1-------------------------2
From this example, velocity is changing but the acceleration is not changing, but the constant value of the acceleration is not zero. Also, notice that the time interval is the same.
Thus, the only option that matches the explanation above is "B".
In equal times its velocity changes by equal amounts.
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