Answer:
length and width=4
height=8
Step-by-step explanation:
Hello to solve this problem we must propose a system of equations of 3x3, that is to say 3 variables and 3 equations.
Ecuation 1
Leght=Width
.L=W
Ecuation 2
To raise the second equation we consider that the length and width of 4 inches less than the height of the box
H-4=W
Ecuation 3
To establish equation number 3, we find the volume of a prism that is the result of multiplying length, width, and height
LxWxH=128
From ecuation 1(w=h)
[tex]HW^2=128[/tex]
solving for H
[tex]H=\frac{128}{W^2}[/tex]
Using ecuation 2
H-4=W
[tex]\frac{128}{W^2}-4=W\\W^3+4W^2-128=0[/tex]
Now we find the roots of the equation, 2 of them are imaginary, and only one results in 4
W=4in
L=4in
to find the height we use the ecuation 2
H-4=W
H=4+W
H=4+4=8
H=8IN
