The simplification of (-2 - 2i)( -4 + 6i) is 20 - 4i
SOLUTION:
In this particular question we have been asked to simplify the given equation containing complex numbers.
The given equation is:
(-2-2i)(-4+6i)
To simplify the equation we have to open the brackets and multiply.
Before we do that we need to know the value of i.
‘i’ is as complex number with a value of [tex]\sqrt-1[/tex] and [tex]i^2[/tex] has a value of -1
So now we can calculate the given expression as follows:
= (-2 - 2i)( -4 + 6i)
[tex]\begin{array}{l}{=(-2 \times-4)+(-2 \times 6 i)+(-2 i \times-4)+(-2 i \times 6 i)} \\\\ {=8-12 i+8 i-12 i^{2}} \\\\ {=8-4 i-12 \times-1} \\\\ {=8+12-4 i} \\\\ {=20-4 i}\end{array}[/tex]
Therefore, the correct option is 20 - 4i.
