1.506 × 10²³ carbon atoms
Explanation:
First we calculate the number of moles of calcium carbonate (CaCO₃) contained in 25 g.
number of moles = mass / molecular weight
number of moles of CaCO₃ = 25 / 100 = 0.25 moles
Now we make use of Avogadro's number which tell us that we have 6.022 × 10²³ molecules (or atoms) in one mole of substance.
Now in our case:
if in 1 mole of CaCO₃ we have 1 × 6.022 × 10²³ carbon atoms
then in 0.25 moles of CaCO₃ we have X carbon atoms
X = (0.25 × 1 × 6.022 × 10²³) / 1
X = 1.506 × 10²³ carbon atoms
Learn more:
Avogadro's number
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