Melanyalexaa
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Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

1 2 3 4 5 6

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 5 from the first bag and an odd tile from the second bag?

Respuesta :

RichardUSA
To answer this question, you can use basic probability: The chance of getting tile number 5 from the first bag is 1/6 as it is for all other tiles in the same bag. The chance of getting an odd tile from the second bag is 3/6 as it is for getting an even tile. By multiplying the two, we get a total probability of 1/12.
onyebuchinnaji

The probability of drawing a tile numbered 5 from the first bag and an odd tile from the second bag is ¹/₁₂

Given;

numbers of tiles in each bag, 1, 2, 3, 4, 5, 6

To find:

the probability of drawing a tile numbered 5 from the first bag and;

an odd tile from the second bag

The first draw: there is only one tile numbered 5

[tex]The \ probability = \frac{1}{6}[/tex]

The second draw: there are 3 odd numbers (1, 3, 5)

[tex]The \ probability = \frac{3}{6} = \frac{1}{2}[/tex]

The combined probabilities:

[tex]The \ probability = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12}[/tex]

Therefore, the probability of drawing a tile numbered 5 from the first bag and an odd tile from the second bag is ¹/₁₂

To learn more about probability, please visit: https://brainly.com/question/24141156

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