In Drosophila, the mutant alleles vermillion (r), on the X chromosome, and cinnabar (n), on an autosome, cause the same phenotype: bright-red eye color instead of the wild type purple. A male from a true-breeding vermillion stock and a female from a true breeding cinnabar stock are crossed. Predict phenotypic ratios among their F1 and F2 progeny, individually for sons and daughters

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22-10-2019
Biology

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In Drosophila, the mutant alleles vermillion (r), on the X chromosome, and cinnabar (n), on an autosome, cause the same phenotype: bright-red eye color instead of the wild type purple. A male from a true-breeding vermillion stock and a female from a true breeding cinnabar stock are crossed. Predict phenotypic ratios among their F1 and F2 progeny, individually for sons and daughters

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silgoni17 silgoni17 · Answer 1 · 2019-10-24T02:22:37+02:00

Answer:

1. F1: Sons: 100% wild-type, daughters: 100% wild-type.

2. F2: Sons: 5:3 bright-red eye color to wild-type, daughters: 1:3 bright-red eye color to wild-type.

Explanation:

In this example two genes in different chromosomes produce the same phenotype: bright-red eye color. First, vermillion gene is in X chromosome, and the vermillion color is a recessive trait, so vermillion mutants should be:

Mutant Females: [tex]X^{r}X^{r}[/tex]

Mutant Males: [tex]X^{r}Y[/tex]

Wild-type Females: [tex]X^{R} X^{R} /X^{R} X^{r}[/tex]

Wild-type Males: [tex]X^{R}[/tex]

Second, cinnabar gene is in an autosome and it's recessive too, so mutants should be:

Mutant males or females: nn

Wild-type: NN

If a vermillion male ([tex]X^{r}YNN[/tex]) is crossed with a cinnabar female [tex]X^{R}X^{R} nn[/tex], it will produce an F1 as in the first Punnett Square. In this case, all sons and daughters are going to be wild-type.

When F1 is crossed, an F2 is produced as in the second and third Punnett Squares. In this case, in daughters, it will produce a phenotypic ratio of 1:3 red eyes to wild-type eyes.

In sons, it will produce a phenotypic ratio of 5:8 red eyes to wild-type eyes.

bratislava bratislava · Answer 2 · 2022-02-02T06:25:44+01:00

The alleles of the chromosomes.

Drosophila is a genus of flies and is often called s small fruit flies. These can linger around the rotten fruit, are called s common fruit flies. As per the vermillion the mutant alleles of the vermilion (r) on the X chromosomes and cinnabar (n) on the autosome cause the same phenotype and bright red eye.

Answer is F1: Sons: 100% the wild-type wild-type. the F2: Sons: 5:3 bright-red eye to wild-type. And 1:3 in wild daughter.

Let the alleles be the F1 and F2, the dominant allele will have more of red and wild purple.

The male from the true vermillion stock and a female from the true-breeding cinnabar stock will show the color of the sons and the daughter as a ratio of 5:3, and 1:2.

Thus the ratio of 1:3 of the wild daughters.

Find out more information about the allele of chromosome.

brainly.com/question/13495528.