A line contains points M(1, 3) and N(5, 0). What is the slope of MN? negative StartFraction 4 Over 3 EndFraction negative StartFraction 3 Over 4 EndFraction StartFraction 3 Over 4 EndFraction StartFraction 4 Over 3 EndFraction

Respuesta :

Answer:

The slope would be -3/4

Step-by-step explanation:

Since, slope of a line having end points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is,

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Here, line segment MN contains end points M(1, 3) and N(5, 0)

i.e.

[tex]x_1 = 1, y_1 = 3, x_2 = 5, y_2 = 0[/tex]

Thus, the slope of line MN would be,

[tex]m=\frac{0-3}{5-1}=\frac{-3}{4}[/tex]

Answer:

The answer would be option (B) (-3/4)

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