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A 30-kg block of ice at 0° C is sliding on a horizontal surface. The initial speed of the ice is 6.1 m/s and the final speed is 4.5 m/s. Assume that the part of the block that melts has a very small mass and that all the heat generated by kinetic friction goes into the block of ice. Determine the mass of ice that melts into water at 0° C.

Respuesta :

Answer:0.748 gm

Explanation:

Given

mass of block =30 kg

initial velocity=6.1 m/s

Final velocity=4.5 m/s

Change in kinetic Energy[tex]=\frac{mv_i^2}{2}-\frac{mv_f^2}{2}[/tex]

[tex]\Delta KE=254.4 J[/tex]

Change in kinetic energy =heat generated by friction=heat  absorbed by ice

[tex]L=3.4\times 10^5 J/kg[/tex]

[tex]254.4=m\times 3.4\times 10^5[/tex]

m=0.748 gm

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