Answer:
the height of the cliff is equal to 108.241 m
Explanation:
given,
initial speed of the stone horizontally = 9 m/s
vertical speed of the stone = 0 m/s
time taken of the trajectory = 4.7 s
using equation of motion
[tex]s = ut + \dfrac{1}{2}at^2[/tex]
[tex]s =0 \times 4.7 + \dfrac{1}{2} \times 9.8 \times 4.7^2[/tex]
[tex]s = 0 + 4.9 \times 4.7^2[/tex]
[tex]s = 4.9 \times 22.09[/tex]
s = 108.241 m
hence, the height of the cliff is equal to 108.241 m
