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• A cable is suspended over a pulley. A 5.0 kg mass is attached to
one end of a cable and 10.0 kg mass is attached to the other end.
When the system is released, the 5 kg mass accelerates upward.
Find the tension in the cable. Ignore the friction, the mass of the
pulley and the mass of the cable.​

Respuesta :

Answer:

Tension= [tex]\frac{20g}{3}[/tex]  (g=acceleration of gravity)

Explanation:

Given that,

A 5Kg and 10Kg are attached by a cable suspended over a pulley.

As 10Kg > 5Kg , the 10 kg mass accelerates down and the 5kg mass accelerates up, let it be a. Let the tension in the cable be T.

So, the equations of motion are

[tex]10g-T = 10a[/tex]

[tex]T-5g=5a[/tex]

Now adding them we get,

[tex]5g=15a[/tex]

[tex]a=\frac{g}{3}[/tex]

Substituting them back in the equation we get,

[tex]10g-10(\frac{g}{3} ) = T[/tex]

[tex]T= \frac{20g}{3}[/tex]

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