Answer:
KE = 2.535 x 10⁷ Joules
Explanation:
given,
angular speed of the fly wheel = 940 rad/s
mass of the cylinder = 630 Kg
radius = 1.35 m
KE of flywheel = ?
moment of inertia of the cylinder
[tex]I = \dfrac{1}{2}mr^2[/tex]
=[tex]\dfrac{1}{2}\times 630\times 1.35^2[/tex]
= 574 kg m²
kinetic energy of the fly wheel
[tex]KE = \dfrac{1}{2}I\omega^2[/tex]
[tex]KE =\dfrac{1}{2}\times 574\times 940^2[/tex]
KE = 2.535 x 10⁷ Joules
the kinetic energy of the flywheel is equal to KE = 2.535 x 10⁷ Joules
