Smedly has just drawn two rectangles. The length of the first rectangle is 4 cm more than the length of the second. The width of the first is 9 cml the width of the second is 6 cm. If the area of the first rectangle is 96cm

Respuesta :

Answer:

The area of the second rectangle is [tex]A=42cm^{2}[/tex]

Step-by-step explanation:

Please see the picture below.

Let´s name the length of the second rectangle as x, so the length of the first rectangle will be 4+x.

The formula of the area of the rectangle is given by

[tex]A=length*width[/tex]

Replacing values:

[tex]96cm^{2}=(4cm+x)*9cm[/tex]

[tex]96cm^{2}=36cm+9cm*x[/tex]

Solving for x:

[tex]96cm^{2}-36cm=9cm*x[/tex]

[tex]60cm=9cm*x[/tex]

[tex]x=\frac{60cm}{9cm}[/tex]

[tex]x=7cm[/tex]

Find the area of the second rectangle:

[tex]A=length*width[/tex]

[tex]A=x*6cm[/tex]

[tex]A=7cm*6cm[/tex]

[tex]A=42cm^{2}[/tex]

Ver imagen Ondinne