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An investment of ​$46 comma 00046,000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned​ 8% interest, the second​ 6%, and the third​ 9%. Total interest from the investments was $ 3720.$3720. The interest from the first investment was 33 times the interest from the second. Find the amounts of the three parts of the investment.

Respuesta :

calculista

Answer:

The amount invested at 8% was $37,459.5

The amount invested at 6% was $1,513.5

The amount invested at 9% was $7,027

Explanation:

Let

x ----> the amount invested at 8%                

y ---> the amount invested at 6%

z ---> the amount invested at 9%

we know that          

[tex]x+y+z=46,000[/tex] ----> equation A

[tex]0.08x+0.06y+0.09z=3,720[/tex] ----> equation B

[tex]0.08x=33(0.06y)[/tex] ----> equation C

Solve the system of equations by calculator (wolfram alpha's tool)

see the attached figure

The solutions are

[tex]x=\$37,459.5\\y=\$1,513.5\\z=\$7,027[/tex]

therefore

The amount invested at 8% was $37,459.5

The amount invested at 6% was $1,513.5

The amount invested at 9% was $7,027

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