For this case we must factor [tex]- \frac {3} {4}[/tex]of the following expression:
[tex]\frac {3} {2} x- \frac {9} {4}y[/tex]
By law of signs of multiplication it is fulfilled that:
[tex]- * - = +\\- * + = -[/tex]
So we have to:
[tex]- \frac {3} {4} * (- 2) = + \frac {6} {4} = + \frac {3} {2}\\- \frac {3} {4} * 3 = - \frac {9} {4}[/tex]
Thus, by factoring we have:
[tex]- \frac {3} {4} (- 2x + 3y)[/tex]
Answer:
[tex]- \frac {3} {4} (- 2x + 3y)[/tex]
