Answer:
0.22 W
Explanation:
given:
MR1= 100 Watts (Joules per second)
M1=0.029 kg
M2=100 kg
Metabolic Rate =MR1*(M1/M2)^(3/4)
=100*(0.029/100)^(3/4)
=0.22 W
Answer:
Metabolic rate is 39.52 W
Solution:
As per the question:
Metabolic Rate, MR' = 100 W
Mass of the animal, m = 100 kg
Mass of the creature, m' = 29 kg
Kleiber's law expresses that the metabolic pace of a creature scales to the 3/4 intensity of the mass.
Now, considering kleiber's law to be true:
Metabolic Rate, [tex]MR = MR'\times (\frac{m'}{m})^{\frac{3}{4}}[/tex]
[tex]MR = 100\times (\frac{29}{100})^{\frac{3}{4}} = 39.52 W[/tex]
