Answer:
42.86m
Explanation:
The first thing we should keep in mind is that the watermelon moves with uniform acceleracion equal to gravity (9.81m / s ^ 2)
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
[tex]\frac {Vf^{2}-Vo^2}{2.g} =Y[/tex]
where
Vf=29m/s= final speed
Vo= initial speed=0m/S
g=gravity=9.81m/s^2
Y= distance traveled(m)
solving
[tex]\frac {Vf^{2}-Vo^2}{2.g} =Y\\\frac {(29m/s)^{2}-(0m/s)^2}{2(9.8m/s^2)} =Y\\Y=42.86m\\[/tex]
the distance traveled by watermelon is 42.86m
The distance which the watermelon must fall freely from rest is 42.91 meters.
Given the following data:
We know that acceleration due to gravity (a) for an object in free fall is equal to 9.8 meter per seconds square.
To find how far (distance) the watermelon must fall freely from rest, we would use the third equation of motion;
[tex]V^2 = U^2 + 2aS[/tex]
Where:
Substituting the given parameters into the formula, we have;
[tex]29^2 = 0^2 + 2(9.8)S\\\\841 = 0 + 19.6S\\\\841 = 19.6S\\\\S = \frac{841}{19.6}[/tex]
Distance, S = 42.91 meters.
Therefore, the distance which the watermelon must fall freely from rest is 42.91 meters.
Read more: https://brainly.com/question/8898885
