Answer:
The answer to your question is:
Explanation:
Data
Jogger
vo = 0 m/s
v2 = 4.55 m/s
t = 3.64 s
Car
vo = 15.8 m/s
v2 = 25.3 m/s
t = 3.64
a)
Formula
a = [tex]\frac{v2 - vo}{t}[/tex]
Jogger
a = [tex]\frac{4.55 - 0}{3.64}[/tex]
a = 1.25 m/s2
b)
Car
a = [tex]\frac{25.3 - 15.8}{3.64}[/tex]
a = 2.61 m/s2
c)
Formula d = vot + 1/2 at2
Jogger
d = (0)(3.64) + 1/2(1.25)(3.64)2
d= 8.3 m
Car
d = (15.8)(3.64) + 1/2(2.61)(3.64)2
d = 57.51 + 17.29
d = 74.8 m
Difference = 74.8 - 8.3 = 66.5 m
Answer:
Listed below
Explanation:
Acceleration can be calculated using the following formula:
[tex]A=\frac{V2-V1}{T}[/tex]
Where:
V2= final velocity
V1=initial velocity
T=time.
A) At rest means that the jogger's initial velocity was of 0 m/s. So we get:
[tex]A=\frac{4.55m/s-0m/s}{3.64}[/tex]
[tex]A=1.25 m/s^s[/tex]
B) [tex]A=\frac{25.3m/s-15.8m/s}{3.64}[/tex]
[tex]A=2.60 m/s^2[/tex]
C) To calculate the distance traveled we have to use the following formula:
[tex]X= X1+V1. (T2-T1)+\frac{1}{2}.a.(T2-T1)^2[/tex]
Where:
X= distance
X1= initial distance (we consider this one as zero as this is not commented on the problem)
V1= initial velocity
T2=final time
T1=initial time
a= acceleration
For the jogger:
[tex]X= 0m/s. (3.64 s)+\frac{1}{2}.1.25m/s^2.(3.64s)^2[/tex]
[tex]X= 8.28 m[/tex]
For the car:
[tex]X= 15.8m/s. (3.64 s)+\frac{1}{2}.2.60m/s^2.(3.64s)^2[/tex]
[tex]X= 74.73 m[/tex]
The car travels travels 66.45 m more than the jogger
