theantman209
contestada

27. Suppose the hare runs 600 inches per second and the tortoise runs
3 inches per second. When the hare wakes up, the tortoise is 1000 feet (or 12.000 inches) ahead. Which equation represents when the hare will catch up with the tortoise? (Hint: If t represents time in seconds
then 3t is the distance in inches the tortoise can travel in t seconds.)
A. 3t = 600t + 12,000
B. 600t = 3t + 12,000
C. 3t - 12,000 = 600t D . 600t = 12,000
Please also show steps.​

Respuesta :

makinziedunn

Answer:

A. 3t = 600t + 12,000

Step-by-step explanation:

It would be A because if the tortoise is going 3 inches per second then that would be your ending point and since the hare is going 600 inches per second then you would have to add 12,000 to 600t because the tortoise is 12,000 inches in front of the hare.

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