Answer:
1186.67 N
Explanation:
u = Initial velocity = 2 m/s
v = Final velocity = 0
s = Displacement = 0.15 m
a = Acceleration
m = Mass = 1200 kg
Equation of motion
[tex]v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-2^2}{2\times 0.15}\\\Rightarrow a=-13.33\ m/s^2[/tex]
Force
[tex]F=ma\\\Rightarrow F=1200\times -13.33\\\Rightarrow F=1186.67\ N[/tex]
The force that the bumper will exert is 1186.67 N
Answer:
F = 16 kN
Explanation:
given,
mass of the car = 1200 kg
distance travel to stop = 15 cm
initial speed of car = 2 m/s
average force = ?
using equation of motion
v² = u² + 2 as
0² = 2² - 2 a × 0.15 ∵ -ve sign because of deceleration
0.3 a = 4
[tex]a = \dfrac{4}{0.3}[/tex]
[tex]a = 13.33\ m/s^2[/tex]
F = m a
F = 1200 × 13.33
F = 15996 N
F = 16 kN
the average force on the bumper is equal to F = 16 kN
