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A 1000-kg car travels along a straight portion of highway at a constant velocity of 10 m/s, due east. The car then encounters an unbanked curve of radius 50 m. The car follows the curve traveling at a constant speed of 10 m/s while the direction of the car changes from east to south. What is the magnitude of the frictional force between the tires and the road as the car negotiates the unbanked curve?

Respuesta :

Manetho

Answer:

2000 N

Explanation:

mass of the car = 1000 kg

Along the curved path v= 10 m/s

radius of the curved path

acceleration a=  [tex]\frac{v^2}{r}[/tex]

=[tex]\frac{10^2}{50}[/tex] = 2m/s^2

friction force F_friction = m×a = 1000×2 = 2000 N

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