Answer:
the acceleration required is 1.37m/s^2
Explanation:
The car is having a constant velocity movement, so if we calculate the time to reach 897m, we can use it to find the acceleration the policeman need to apply to reach the car.
[tex]x=v*t\\t=\frac{x}{v}\\t=\frac{897m}{24.8m/s}\\t=36.17s[/tex]
the policeman is traveling with a constant acceleration starting from rest so:
[tex]x=\frac{1}{2}*a*t^2\\\\a=\frac{2*x}{t^2}\\\\a=1.37 m/s2[/tex]