Answer:
a = 2, b = 6 and c = 10
Step-by-step explanation:
Here arithmetic sequence is given as −2, a, b, c, 14
First term, f = -2
Fifth term, f + 4d = 14
We have
-2 + 4d = 14
d = 4
Common difference , d = 4
We know that n th term of AP is
[tex]t_n=f+(n-1)d[/tex]
We need to find a,b,c
a = f + d = -2 + 4 = 2
b = f + 2d = -2 + 2 x 4 = 6
c = f + 3d = -2 + 3 x 4 = 10
So
a = 2, b = 6 and c = 10