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If the angular magnification of an astronomical telescope is 43 and the diameter of the objective is 83 mm, what is the minimum diameter of the eyepiece required to collect all the light entering the objective from a distant point source located on the telescope axis?

Respuesta :

Answer:

[tex]d_{eye\ piece} =1.93\ mm[/tex]

Explanation:                    

angular magnification (m_θ) = 43                        

diameter of the objective = 83 mm              

                                          = 0.083 m

The minimum diameter of eyepiece                        

[tex]d_{eye\ piece} = \dfrac{d_{object}}{m_\theta}[/tex]

[tex]d_{eye\ piece} = \dfrac{83}{43}[/tex]                        

[tex]d_{eye\ piece} =1.93\ mm[/tex]                                  

Hence, The minimum diameter of the eyepiece required = 1.93 mm

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