Answer:2) less than
Explanation:
Given
specific heat of ice[tex](c_{ice})=2 J/g^{\circ}[/tex]
specific of water[tex](c_{water})=4 J/g^{\circ}[/tex]
energy required to raise the temperature of 10 g of ice from [tex]-5 to -4 ^{\circ}[/tex]
[tex]E_1=m\times c_{ice}\times \Delta T[/tex]
[tex]E_1=10\times 2\times 1=20 J[/tex]
For water
[tex]E_2=m_{water}\times c_{ice}\times \Delta T[/tex]
[tex]E_2=10\times 4\times 1=40 J[/tex]
Thus [tex]E_2> E_1[/tex]