Answer:
1836 N
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
Equation of motion
[tex]v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-10^2}{2\times 49}\\\Rightarrow a=-1.02\ m/s^2[/tex]
[tex]F=ma\\\Rightarrow F=1800\times 1.02\\\Rightarrow F=1836\ N[/tex]
The frictional force provided by the brakes is 1836 N
