Answer:
The roots of this quadratic equation are real and unequal
Step-by-step explanation:
Given quadratic equation is x²-4x-32
Now to check the nature of this quadratic we have to find the discriminant
D = b²-4ac ,
For real numbers a,b,c
if D=0 then root are real and equal
D>0 then roots are real and unequal
D<0 then roots are imaginary
Now from given equation
x²-4x-32 here a=1 , b=-4 , and c=-32
so D=b²-4ac
D=(-4)²-4(1)(-32)
D=16+128
D=144
so, here D>0
Hence we can say that the given quadratic equation is Real and unequal
