Answer:
0.26 m/s^2
Explanation:
We're asked to find the acceleration of a body given the net force acting on it and it's mass.
To do this, we use Newton's second law.
The acceleration of a boy on a skateboard is [tex]0.26 \mathrm{ms}^{-2}[/tex]
Explanation:
According to Newton’s second law of motion, the unbalanced force acting on an object will be equal to the product of the mass with the acceleration of the object. So if a boy is riding a skateboard, forward force will be acting on the object which will be helping him to ride it.
So this forward unbalanced force will be equal to the product of total mass of boy and skateboard with the acceleration exerted by boy on the skateboard. Thus,
[tex]\text {Force}=m \times a[/tex]
In the present case,
[tex]\begin{aligned} \text {Unbalanced Forward Force on Boy} \\ &=\text {Total} \text {Mass of boy and skateboard} \\ & \times \text {Acceleration} \text { of boy on skateboard } \end{aligned}[/tex]
So,
[tex]15 N=58 \mathrm{kg} \times \text { Acceleration of boy on skateboard }[/tex]
Thus,
[tex]\text {Acceleration of boy on skateboard}=\frac{15}{58}[/tex]
[tex]\therefore \text { Acceleration of boy on skateboard } =0.26 \mathrm{ms}^{-2}[/tex]
