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Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. Subtract the electronegativities for the following pairs of elements and predict whether they form ionic bonds.

Electronegativity difference of Na and F: 

yes

no


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Respuesta :

Answer:

Yes. They will form an  ionic bond.

Explanation:

Electronegativity of fluorine is 4 and of sodium is 0.9 so

the difference is 4 - 0.9 = 3.1.

Answer:

Yes

Explanation:

Electronegativity value of Flourine (F)  = 3.98

Electronegativity value of Sodium (Na) = 0.93

Electronegativity difference = 3.98 - 0.93 = 3.05

Since the electronegativity difference is greater than 1.5, it means the bond formed would be an ionic bond.

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