Answer:
Q=0.000604 m³/s
Explanation:
Given that
d₁=5 cm
d₂=1 cm
P= 30 KPa
Density of water ,ρ=1000 kg/m³
As we know that volume flow rate Q given as
[tex]Q=A_1A_2\sqrt{\dfrac{\dfrac{2\Delta P}{\rho}}{A_1^2-A_2^2}}[/tex]
[tex]A_1=\dfrac{\pi}{4}\times 0.05^2\ m^2[/tex]
A₁=0.0019 m²
[tex]A_2\dfrac{\pi}{4}\times 0.01^2\ m^2[/tex]
A₂=0.000078 m²
[tex]Q=0.0019 \times 0.000078 \sqrt{\dfrac{\dfrac{2\times 30\times 1000}{1000}}{0.0019^2-0.000078^2}}\ m^3/s[/tex]
Q=0.000604 m³/s
