[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$693\\ r=rate\to 4.6\%\to \frac{4.6}{100}\dotfill &0.046\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &13 \end{cases}[/tex]
[tex]\bf A=693\left(1+\frac{0.046}{12}\right)^{12\cdot 13}\implies A=693(1.0038\overline{3})^{156}\implies A\approx 1160.68[/tex]
