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From the top of a cliff, a person throws two stones. The stones have identical initial speeds, but stone 1 is thrown downward at some angle and stone 2 is thrown at the same angle upward. Neglecting air resistance, which stone, if either, strikes the water with greater velocity? Defend your response.

Respuesta :

Answer:

Stone 2

Explanation:

Let's call the height of the top of the cliff of H. The stone 1 was thrown downward with velocity v₀ and describes an accelerated movement. By the Torricelli's equation, the velocity that it strikes the water is

[tex]v_{max} = \sqrt{2gH}[/tex], where g is the gravity acceleration.

Stone 2 was thrown updown, so it will reach an height H' and then will follow on an accelerated moviment too, but now:

[tex]v'_{max} = \sqrt{2gH'}[/tex]

Because H'> H and vmax is directly proportional to H

v'max > vmax