Answer:
[tex]x-5y=12[/tex] and [tex]3x+2y=-15[/tex]
Step-by-step explanation:
The first system is
[tex]x-5y=-12[/tex] and [tex]3x+2y=-15[/tex]
We substitute x=-3 and y=-3
[tex]-3-5*-3=12\ne-12[/tex] and [tex]3*-3+2*-3=-15[/tex]
Both equations are not satisfied
The next system is
[tex]x-5y=12[/tex] and [tex]3x+2y=-15[/tex]
We substitute x=-3 and y=-3
[tex]-3-5*-3=12[/tex] and [tex]3*-3+2*-3=-15\ne15[/tex]
Both equations are satisfied
The next system is
[tex]x-5y=-12[/tex] and [tex]3x+2y=15[/tex]
We substitute x=-3 and y=-3
[tex]-3-5*-3=12\ne12[/tex] and [tex]3*-3+2*-3=-15[/tex]
Both equations are not satisfied
The next system is
[tex]x-5y=12[/tex] and [tex]3x+2y=15[/tex]
We substitute x=-3 and y=-3
[tex]-3-5*-3=12\ne-12[/tex] and [tex]3*-3+2*-3=-15[/tex]
Both equations are not satisfied
Answer:
The answer is C
Step-by-step explanation:
x-5y=12 and 3x + 2y =15
