Answer:
Explanation:
Given
velocity of spaceship =400 m/s
at angle of [tex]40^{\circ}[/tex] from Positive Y axis towards negative x axis
acceleration of Spaceship=[tex]0.5 m/s^2[/tex]
at an angle of [tex]30^{\circ}[/tex] from positive x axis towards the negative x axis
[tex]\vec{v}=400\left ( -\sin(40)\hat{i}+\cos (40)\hat{j}\right )[/tex]
[tex]\vec{v}=-257.11\hat{i}+306.41\hat{j}[/tex]
acceleration
[tex]\vec{a}=0.5\left ( \cos (30)\hat{i}-\sin (30)\hat{j}\right )[/tex]
[tex]\vec{a}=0.433\hat{i}-0.25\hat{j}[/tex]