Answer:
(a) The probability that Christine fails the course is 0.411.
(b) The probability that Christine finds a tutor given that she fails the course is 0.586.
Step-by-step explanation:
Let the events be:
X = Christine fails the course.
Y = Christine finds a tutor.
Given:
[tex]P(X|Y)=0.33\\P(X|Y^{c})=0.63\\P(Y)=0.73[/tex]
(a)
Compute the probability that Christine fails the course as follows:
[tex]P(X)=P(X|Y)P(Y)+P(X|Y^{c})P(Y^{c})\\=(0.33\times0.73)+(0.63\times[1-0.73])\\=0.411[/tex]
Thus, the probability that Christine fails the course is 0.411.
(b)
Compute the probability that Christine finds a tutor given that she fails the course as follows:
[tex]P(Y|X)=\frac{P(X|Y)P(Y)}{P(X)}=\frac{0.33\times 0.73}{0.411}= 0.586[/tex]
Thus, the probability that Christine finds a tutor given that she fails the course is 0.586.