Answer:
V₂ = 5 L
Explanation
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 3.2 L
Initial pressure = 1 atm
Initial temperature = 40 °C (40 +273 = 313 K)
Final temperature = 20°C (20+273 = 293 K)
Final pressure = 0.60 atm
Final volume = ?
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1 atm × 3.2 L × 293 K / 313 K × 0.60 atm
V₂ = 937.6 atm .L. K / 187.8 K . atm
V₂ = 5 L
