Answer:
200.4 N
Explanation:
We start by finding the acceleration acting on the toothpick. Its motion is a uniformly accelerated motion, so we can use the equation
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
In this problem we have
v = 0 (since it comes to a stop)
u = 224 m/s
a = ?
s = 15 mm = 0.015 m is the stopping distance
Solving for a, we find the acceleration
[tex]a=\frac{v^2-u^2}{2s}=\frac{0-224^2}{2(0.015)}=-1.67\cdot 10^6 m/s^2[/tex]
Now, we know that the mass of the toothpick is
[tex]m=0.12 g = 0.12 \cdot 10^{-3} kg[/tex]
Therefore, we can find the force exerted on it by using Newton's second law:
[tex]F=ma=(0.12\cdot 10^{-3})(-1.67\cdot 10^6)=-200.4 N[/tex]
So, the magnitude of the force is 200.4 N.