Answer:
Real
The same size
Inverted
Explanation:
Given,
Object's height, h₀ = 4 cm
The distance between the object and mirror, u = 10 cm
The focal length of the mirror, f = 5 cm
The mirror formula is given by the relation
[tex]\frac{1}{f} =\frac{1}{u} +\frac{1}{v}[/tex]
Substituting the given values in the above equation according to the sign convention
[tex]\frac{1}{-5} =\frac{1}{-10} +\frac{1}{v}[/tex]
v = -10 cm
Therefore, the image distance from the concave mirror is v = 10 cm from the mirror, which is at the same spot of the object.
The magnification factor is given by the formula
M = - v/u = h₁/h₀
Where
h₁/h₀ = - v/u
Therefore the height of the image
h₁ = -(v/u)h₀
Substituting the values in the equation according to the sign convention
h₁ = -(-10/-10)x4
= -4 cm
Therefore, the height of the image is, h₁ = -4 cm
This implies that the image formed is the same size as the object, and the negative indicates the image formed is inverted.
