Answer:
Explanation:
The spring constant, k, represents stiffness of a spring. Its definition is force divided by displacement which is how far the spring stretches.
In this case, the mass and hence the force is the same. The largest spring constant is the stiffest (more difficult to stretch) spring which stretches the least. So the answer is D.
The equilibrium condition and Hooke's law allow us to find the result for which spring has the greatest constant of the spring is:
Hooke's law states that the restoring force in a spring is proportional to the elongation.
F = - k x
Where F is the force, k the spring constant, and x the elongation from equilibrium position.
In the attachment we see a diagram of the forces. They indicate that the plus is the same therefore the force of the mass on each spring is equal, write the equilibrium equation.
F - W = 0
kx = m g
[tex]k = \frac{m g }{x}[/tex]
They indicate the amount stretched by each spring.
Spring Elongation (cm)
A 25
B 10
C 100
D 1
From the equation we can see that the spring constant is greater as the smallest elongations therefore the spring with the greatest constant is D.
In conclusion using the equilibrium condition and Hooke's law we can find the result for which spring has the greatest spring constant is:
Learn more about Hooke's law here: brainly.com/question/18771646
