Answer:
2687.7 N
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
When he will reach the ground his speed will be 3.2 m/s but will travel 30 cm down
[tex]v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-3.2^2}{2\times 0.3}\\\Rightarrow a=-17.067\ m/s^2[/tex]
Force
[tex]F=m(g-a)\\\Rightarrow F=100\times (9.81-(-17.067))\\\Rightarrow F=2687.7\ N[/tex]
The force on the legs will be 2687.7 N
